321zigzag

04-10-2010, 06:46 PM

So Gin has a 13 km Bankai. Let's assume he can, in fact, wield said Bankai, and not be slowed to a crawl by the ridiculous weight thereof, wind resistance, etc. What it means that the blade of his sword is 13 km long:

1) AoE. Gin can sit and spin (literally) and cut through out everything in a 13 km radius (unless it's strong enough to block a Bankai). That's approximately 530 square km of devastation (13*13*3.14). For comparison, the city of New York covers 780 square km (acc. to Wikipedia); the urban center of Tokyo (the 23 special wards) covers 621.9 square km. In other words, Gin could destroy Tokyo in two slashes. There have been more powerful *focused* attacks in Bleach, but nothing comparable in terms of blast radius (though exploding WW might have managed it).

2) Speed. Again, let's assume that Gin can ignore inconvenient physical facts like weapon weight and air resistance, and that his weapon doesn't deform, ie, the blade remains straight. When a wheel, or a fan blade, spins, a point on the edge will move faster than a point near the axis of rotation; both points are moving around the center at the same speed, but the point further from the center has farther to move to complete its turn.

Now. Say that Gin is being lazy, and slashes in front of him - a 180 degree arc - in one second. In that second, the tip of his blade, 13 km away, must cover that same 180 degrees, half of a circle, around the circumference of a circle 13 km in radius. The tip of Gin's blade, that is, will be moving (26*3.14*0.5) = 40.82 km/sec, or 40820 m/sec. The speed of sound is 340.29 m/sec at sea level; Gin's sword is moving at approximately Mach 120. (Yes, this doesn't compare to being kicked at the speed of light (3*10^9 m/s). Good luck dodging it anyway.)

[And note that this is a very low-end estimate; Bleach characters can swing their swords much faster than that.]

3) Power. If the tip of Gin's blade is moving at 40820 m/s, (and note that the muzzle velocity of a M16 rifle is only 975 m/s) how much kinetic energy does it have? Now, obviously, something's screwy with the mass of Gin's 13 km Bankai, or he wouldn't be able to lift it at all, much less hold it rigidly outwards such that it'd be stiff its whole length (I hear porn stars have the same problem). But we can throw some numbers out. Your basic Japanese sword is approx. 5 cm wide and 0.5 cm thick (I'm mostly guessing here, but I do have a sword sitting next to me to guess from); let's say that Gin's 13 km Bankai blade is (5*0.5*1300000) = 3,250,000 cubic cm of steel. The average density of steel is 7.85 grams/cm3; Gin's Bankai weighs approx. 25,512.5 kg, or approx. 56,127.5 lbs, just over 28 tons...

... and here I stop. Why? Because ;););););) calculus, that's why. Anyone brave enough to try and figure out the rotational kinetic energy of Gin's Bankai has my sincere admiration (http://en.wikipedia.org/wiki/Kinetic_energy). But you know what? I'll go out on a limb and say that it's OVER 9000.

1) AoE. Gin can sit and spin (literally) and cut through out everything in a 13 km radius (unless it's strong enough to block a Bankai). That's approximately 530 square km of devastation (13*13*3.14). For comparison, the city of New York covers 780 square km (acc. to Wikipedia); the urban center of Tokyo (the 23 special wards) covers 621.9 square km. In other words, Gin could destroy Tokyo in two slashes. There have been more powerful *focused* attacks in Bleach, but nothing comparable in terms of blast radius (though exploding WW might have managed it).

2) Speed. Again, let's assume that Gin can ignore inconvenient physical facts like weapon weight and air resistance, and that his weapon doesn't deform, ie, the blade remains straight. When a wheel, or a fan blade, spins, a point on the edge will move faster than a point near the axis of rotation; both points are moving around the center at the same speed, but the point further from the center has farther to move to complete its turn.

Now. Say that Gin is being lazy, and slashes in front of him - a 180 degree arc - in one second. In that second, the tip of his blade, 13 km away, must cover that same 180 degrees, half of a circle, around the circumference of a circle 13 km in radius. The tip of Gin's blade, that is, will be moving (26*3.14*0.5) = 40.82 km/sec, or 40820 m/sec. The speed of sound is 340.29 m/sec at sea level; Gin's sword is moving at approximately Mach 120. (Yes, this doesn't compare to being kicked at the speed of light (3*10^9 m/s). Good luck dodging it anyway.)

[And note that this is a very low-end estimate; Bleach characters can swing their swords much faster than that.]

3) Power. If the tip of Gin's blade is moving at 40820 m/s, (and note that the muzzle velocity of a M16 rifle is only 975 m/s) how much kinetic energy does it have? Now, obviously, something's screwy with the mass of Gin's 13 km Bankai, or he wouldn't be able to lift it at all, much less hold it rigidly outwards such that it'd be stiff its whole length (I hear porn stars have the same problem). But we can throw some numbers out. Your basic Japanese sword is approx. 5 cm wide and 0.5 cm thick (I'm mostly guessing here, but I do have a sword sitting next to me to guess from); let's say that Gin's 13 km Bankai blade is (5*0.5*1300000) = 3,250,000 cubic cm of steel. The average density of steel is 7.85 grams/cm3; Gin's Bankai weighs approx. 25,512.5 kg, or approx. 56,127.5 lbs, just over 28 tons...

... and here I stop. Why? Because ;););););) calculus, that's why. Anyone brave enough to try and figure out the rotational kinetic energy of Gin's Bankai has my sincere admiration (http://en.wikipedia.org/wiki/Kinetic_energy). But you know what? I'll go out on a limb and say that it's OVER 9000.