Ultimate combatant

01-19-2013, 02:05 PM

I noticed an interesting thing in Chapter 244, pages 12, 13 and 14.

Spaceship travels from Earth to Jupiter almost instantly.

From quick search, I found that distance between Earth and Jupiter when they are the closest to each other is 628,743,036 km. Since we are looking for minimal speed and they didn't land on Jupiter, we will decrease the distance to 600.000.000 km (in addition, it will make a result nicer).

600.000.000 km=6,0*10^8 km=6,0*10^11 m

Speed of light is around c=3,0*10^8 m/s

Now, we will assume the spaceship travelled in a straight line making it the shortest possible distance.

v=v0+a*t

We will assume that spaceship needed no time for acceleration and its final speed remained. So we will assume that spaceship was already at its greatest speed from beginning, which is not the case. Therefore, a=0.

So, v[max]=v=v0.

v=s/t

s=6,0*10^11 m

So, what about the time? Is it less than a second, 5 seconds, 10 seconds, a minute, I will leave it up to you.

I will just show for a few different times.

If they travelled for 60 seconds:

v=6,0*10^11 m/60 s

v=1,0*10^10 m/s

v=33,3*c

There are three counter arguments I could think of.

The best one would be that the numbers I used are wrong.

Another one is that the formula I used are wrong or that I made a mistake when calculating.

And the third one is that there is no reason to use calculations in different verse, or that Dragon Ball is not supposed to make sense or that Dragon Ball is a different Universe and that we shouldn't use our informations about such things.

What do you think?!! :D

Spaceship travels from Earth to Jupiter almost instantly.

From quick search, I found that distance between Earth and Jupiter when they are the closest to each other is 628,743,036 km. Since we are looking for minimal speed and they didn't land on Jupiter, we will decrease the distance to 600.000.000 km (in addition, it will make a result nicer).

600.000.000 km=6,0*10^8 km=6,0*10^11 m

Speed of light is around c=3,0*10^8 m/s

Now, we will assume the spaceship travelled in a straight line making it the shortest possible distance.

v=v0+a*t

We will assume that spaceship needed no time for acceleration and its final speed remained. So we will assume that spaceship was already at its greatest speed from beginning, which is not the case. Therefore, a=0.

So, v[max]=v=v0.

v=s/t

s=6,0*10^11 m

So, what about the time? Is it less than a second, 5 seconds, 10 seconds, a minute, I will leave it up to you.

I will just show for a few different times.

If they travelled for 60 seconds:

v=6,0*10^11 m/60 s

v=1,0*10^10 m/s

v=33,3*c

There are three counter arguments I could think of.

The best one would be that the numbers I used are wrong.

Another one is that the formula I used are wrong or that I made a mistake when calculating.

And the third one is that there is no reason to use calculations in different verse, or that Dragon Ball is not supposed to make sense or that Dragon Ball is a different Universe and that we shouldn't use our informations about such things.

What do you think?!! :D